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Question

The number of partial fraction of 3x2+70x+93(x−1)4 is

A
3
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B
4
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C
5
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D
2
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Solution

The correct option is D 3
by subsitution method
x1=tx=t+1
3(t+1)2+70(t+1)+93t4
3t2+76t+166t4=3t2+76t3+166t4
3(x1)2+76(x1)3+166(x1)4
So, 3 partial fractions.

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