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Question

The number of particles crossing unit area perpendicular to X-axis in unit time is given by N=−D(n2−n1)(x2−x1) where n1 and n2 are number of particles per unit volume for the value of x meant to x2 and x1, D is the diffusion constant. The dimensions of D are :

A
LT1
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B
L2T1
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C
LT
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D
L1T
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Solution

The correct option is B L2T1
N=D(n2n1)(x2x1)
N is the number of particles per unit area per unit time, so it has dimensions as L2T1.
n1,n2 are the number of particles per unit volume, so they have dimensions as L3.
Dimensions of x1,x2 are M0L1T0.
Putting in equation and solving, L2T1=[D]×L3L
Thus we get dimensions of D as L2T1.

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