Question

The number of people suffering from disease X in various months of 2012 is represented by the histogram and the corresponding frequency polygon.

If the area of half of the histogram is given as 75 $uni{t}^2$, calculated the area of frequency polygon.

• A. 75 $uni{t}^2$
• B. 100 $uni{t}^2$
• C. 150 $uni{t}^2$
• D. 175 $uni{t}^2$

Answer 1

The correct option is C 150 $uni{t}^2$

Area of the frequency polygon and histogram drawn for the same data and on the same axes are equal.

In this case, frequency polygon is drawn for the exclusive class intervals distribution because the histogram is made only for the exclusive intervals.

Half of the area of Frequency polygon = 75 $uni{t}^2$.
The full area of Frequency polygon = Area of the Histogram.

Hence, area of the histogram $=2\times 75$ $uni{t}^2$ = 150 $uni{t}^2$.