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Permutation under Restriction

The number of...

Question

The number of permutations of M things out of A things of one kind B things of the second kind and C things of other kinds is $\frac{(A + B + C)!}{A! B! C!}$

A

True

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B

False

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Solution

The correct option is B False
According to the permutation of n things, those are not all different
The number of permutation of given problem is $\frac{M!}{A! B! C!}$

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Permutation under Restriction

Standard XII Mathematics

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