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Question

The number of permutations of the word AUROBIND in which vowels appear in the alphabetical order, is

A
8P4
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B
8C4
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C
4!×8C4
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D
5!×8C5
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Solution

The correct options are
A 8P4
C 4!×8C4
There are four vowels, A,U,O,I
We first choose four positions to put these four vowels in alphabe order. This can be done in 8C4 ways.
Now, the remaining four positions can be filled by the four consonants in 4! ways.
Hence, required number of permutations =8C4×4!=8P4

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