Question

The number of permutations that can be made out of the letters of the word “EQUATION” which start with a consonant and end with a consonant is

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Consonants occupy 2 ends in ${}^3{\text{P}}_2$ ways remaining 6 letters occupy 6 places in 6! Ways
So the required number of arrangements = ${}^3{\text{P}}_2.6!=3!6!$