Question

The number of petrol engine cars in State-3 is what percent more than the number of diesel engine cars in State-1?

• A. 100
• B. 200
• C. 300
• D. 125
• E. 225

Answer 1

The correct option is A

100

Number of cars in State-I = 700 x $\frac{14}{100}$ = 98

Number of diesel cars in State-I = 98 x $\frac{3}{7}$ = 42

Number of cars in State-3 = 700 x $\frac{32}{100}$ = 224

Number of petrol cars in State-3 = 224 x $\frac{3}{8}$ = 84

$\therefore$ Required percentage = $\frac{84-42}{42}$ = 100%

Alternate method: Required percentage = [$\frac{(32\times \frac{3}{8})-(14\times \frac{3}{7})}{14\times \frac{3}{7}}$] x 100 = 100%