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Question

The number of photons emitted per second by a 62 W source of monochromatic light of wavelength 4800 A0 is :

A
1.5×1019
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B
1.5×1020
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C
2.5×1020
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D
4×1020
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Solution

The correct option is B 1.5×1020
Power of the source = 62 watt
Energy emitted in a second = 62 joules
So, number of photons emitted in a second =62λhC

=62×4800×10106.626×1034×3×108 photons / sec
=1.4962×1020 photons / sec
1.5×1020 photons /sec
So, the answer is option (B).

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