Question

The number of planes that are equidistant from four non-coplanar points is-

• A. $3$
• B. $4$
• C. $7$
• D. $9$

Answer 1

The correct option is C $7$

Let the point be $A,B,C$ and $D$
The number of planes which have three points on one side and the fourth point on the other side is $4$. And the number of planes which have two points on each side of the plane is $3$. Therefore Total number of plane is $7$.