The number of points of intersection of $2 y = 1$ and $y = sin x, - 2 π \leq x \leq 2 π$ .

1

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Solution

The correct option is B $4$
$y = \frac{1}{2}, y = sin x, - 2 π \leq x \leq 2 π$
$sin x = \frac{1}{2}, - 2 π \leq x \leq 2 π$
We will have four solution $\frac{π}{6}, \frac{5 π}{6}, \frac{- 7 π}{6}, \frac{- 11 π}{6} .$

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