The number of points of intersection of f(x)=x3ā9x2+27xā27 and g(x)=x is
A
1.0
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B
1
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C
1.00
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D
01
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Solution
Given: f(x)=x3−9x2+27x−27 f(x) can be written as: f(x)=x3+3(−3)x2+3(−3)2x−33⇒f(x)=(x−3)3
Whose graph, we can draw as:
Now, to find the number of points of intersection of f(x)&g(x), let's draw both of them on the same graph as:
Thus, the graphs intersect each other at 1 point.