The number of points such that the tangents from it to three given circles are equal in length, is

1

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2

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3

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4

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Solution

The correct option is B $1$
$s_{1} = 0, s_{2} = 0$ and $s_{3} = 0$ are given $e q^{n}$ of three circle.
So, one radical axis is given by
$s_{1} - s_{2} = 0$ this a equation of line $L_{1} .$
and other radical axis is given by
$s_{1} - s_{3} = 0$ this is another equation of line $L_{2} .$
By intersection of line $L 1$ and $L 2,$
we find a point from which can draw tangents of
equal length to given three circle.
So, there is only one point exist

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