Question

The number of positive divisors of $216$ is

• A. $16$
• B. $6$
• C. $8$
• D. $12$

Answer 1

The correct option is A $16$

For a number $N$, number of divisors are given by the formula

$(a+1)(b+1)(c+1)(d+1)....$

When we write $N$ in terms of its prime factor

$N=$ $P^a{Q}^b{R}^c...$

Here $P,Q,R$ are the prime factors of the number $N$.

So for $216=$ $2^3{3}^3$

So total number of divisors are given by $4\times 4=16$