wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of positive integers satisfying the equation x+log10(2x+1)=xlog105+log106 is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
infinite
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1
log1010x+log10(2x+1)=log105x+log106
10x(2x+1)=5x6
2x(2x+1)=6 (5x0)(2x)2+2x6=02x=2 or 2x=3 (Not possible)
2x=2
x=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon