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Question

The number of positive integers satisfying the inequality (n+1)Cn2n+1Cn1 100 is

A
9
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B
8
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C
5
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D
7
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Solution

The correct option is B 8
(n+1)n(n1)6(n+1)n2100
(n+1)n(n4)600
Also n20=n2
and n10=n1
n2
Possible values are n=2,3,4,5,6,7,8,9

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