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Question

The number of positive integral solutions of x+y+z=n,nϵN,n3, is

A
n1C2
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B
n1P2
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C
n(n1)
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D
none of these
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Solution

The correct option is B n1C2
Consider n=3,
Hence we get
x+y+z=3
Since x,y,z all are non-zero positive integers.
x=y=z=1
Hence number of solutions is 1.
=2C2
=31C2
Consider n=4
x+y+z=4
x=1,y=1,z=2
x=2,y=1,z=1
x=1,y=2,z=1
Hence there are 3 solutions.
=3C2
=41C2
Hence for x+y+x=n and n3
The number of positive integral solutions is n1C2

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