The correct option is B n−1C2
Consider n=3,
Hence we get
x+y+z=3
Since x,y,z all are non-zero positive integers.
x=y=z=1
Hence number of solutions is 1.
=2C2
=3−1C2
Consider n=4
x+y+z=4
x=1,y=1,z=2
x=2,y=1,z=1
x=1,y=2,z=1
Hence there are 3 solutions.
=3C2
=4−1C2
Hence for x+y+x=n and n≥3
The number of positive integral solutions is n−1C2