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Question

The number of positive roots of x7+3x3−2x3+7x+2=0

A
atleast two
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B
atmost two
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C
atmost one
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D
atleast one
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Solution

The correct option is A atleast two

Consider the given function:

x7+3x32x3+7x+2=0

usingtodescartesrulesign:

x7+3x32x3+7x+2=0

changeofsing:

++++

ithaspositiverealroot=2

Hence this is the answer.


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