The number of possible alkynes with molecular formula $C_{5} H_{8}$ is:

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Solution

The correct option is B 3
$C_{5} H_{8}$ (pentyne) shows the following three isomers.

$C H_{3} - C H_{2} - C H_{2} - C \equiv C H$ : Pent -1 yne

$C H_{3} - C H_{2} - C \equiv C - C H_{3}$ : Pent -2 yne

$C H_{3} - C H_{3} | C H - C \equiv C H$ : 3-methyl but -1-yne

Option B is correct.

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