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Question

The number of possible isomers for compound C2H3Cl2Br is


A

2

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B

3

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C

4

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D

5

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Solution

The correct option is B

3


C2H3Cl2Br three isomers are possible

CH3C Cl ClBr 1-bromo-1,1-dichloroethane

BrCH2CH Cl Cl 1-bromo-2,2-di-chloroethane

ClCH2CH Br Cl 1-bromo-1,2-dichloroethane


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