The number of possible isomers for the complex $[C o (e n)_{2} C l_{2}] C l$ will be: ( $e n$ = ethylenediamine)

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Solution

The correct option is A $3$
$[C o (e n)_{2} C l_{2}] C l$
Possible isomers:
(i) Geometrical isomers

In the trans form, a plane of symmetry present and so trans form is optically inactive but cis is optically active. Total number of stereoisomers $= 2 + 1 = 3$

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Possible isomers:
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