The number of possible isomers for the complex $[C o (e n)_{2} C l_{2}] C l$ will be: ( $e n$ = ethylenediamine)

3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $3$
$[C o (e n)_{2} C l_{2}] C l$
Possible isomers:
(i) Geometrical isomers

In the trans form, a plane of symmetry present and so trans form is optically inactive but cis is optically active. Total number of stereoisomers $= 2 + 1 = 3$

Suggest Corrections

Similar questions

[C o (e n_{2}) C l_{2}] C l

[C o (e n)_{2} C l_{2}] C l

Number of possible isomers for the complex $[C o (e n)_{2} C l_{2}] C l$ will be (en = ethylenediamine)

{[C o {C l}_{2} (e n) {({N H}_{3})}_{2}]}^{+}

The sum of coordination number and oxidation number of the metal M in the complex $[M (e n)_{2} (C_{2} O_{4})] C l$ (where, en is ethylenediamine) is

Join BYJU'S Learning Program