Question

The number of possible outcomes in a throw of $5$ ordinary dice in which at least one of the dice shows an odd number is

• A. $6^5-1$
• B. $3^5$
• C. $6^5-3^5$
• D. $5^5$

Answer 1

The correct option is C $6^5-3^5$

Total possible outcome $=6\times 6\times \cdots 5\text{times}=6^5$

The total number of ways when no odd outcomes (only even) numbers is

$3\times 3\times \cdots$ to $5$ times $=3^5$.

Therefore the required number of ways is
$=6^5-3^5$