The number of possible pairs of numbers, whose product is 5400 and HCF is 30, is
Ans given:- 2 pairs
H.C.F of numbers is 30
So required numbers should be multiple of 30.
Let the numbers are 30a and 30b
The product of the numbers = 5400
Then,
30a x 30b = 5400
=> ab = 6
The co-primes or possible pairs of product 6 either (1, 6) and (2,3), or (6,1) and (3, 2)
that means
a x b = 6
30a x 30b = 5400
30 x 180 = (30,180) = 5400 (there (1, 6) a = 1 , b = 6)
60 x 90 = (60,90) = 5400 (there (2, 3) a = 2 , b = 3)
Thus,only two pairs are possible, whose product is 5400 and H.C.F. is 30.