The number of possible tangents which can be drawn to the curve $4 x^{2} - 9 y^{2} = 36,$ which a perpendicular to the straight line $5 x + 2 y - 10 = 0$ is:

0

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1

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Solution

The correct option is A $0$
$m_{1}$ is the slope of tangent
$m_{2}$ is the slope of straight line

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Similar questions

4 x^{2} - 9 y^{2} = 36

5 x + 2 y - 10 = 0

4 x^{2} + 9 y^{2} = 1

2 y + x = 0

\frac{x^{2}}{9} - \frac{y^{2}}{4} = 1

5 x + 2 y = 10

\frac{x^{2}}{9} - \frac{y^{2}}{4} = 1

5 x + 2 y = 10

4 x^{2} + 9 y^{2} = 36

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