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Question

The number of primary alcohols possible with the formula C4H10O is :

A
2
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B
3
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C
4
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D
5
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Solution

The correct option is D 2
Primary alcohol means CH2OH
So remaining carbons are =3
Total no. of radical of 3C are =2
CCC and CC|C
So, total possible primary alc. are =2

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