Question

The number of primary alcohols possible with the formula $C_4{H}_{10}O$ is :

• A. $2$
• B. $3$
• C. $4$
• D. $5$

Answer 1

Answer: (A)

$2$

Primary alcohol means $-{CH}_2-OH$
So remaining carbons are $=3$
Total no. of radical of $3C$ are $=2$
$C-C-C-$ and $C-\underset{|C}{C}-$
So, total possible primary alc. are $=2$