The number of prime factors in $1955$ are

5

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8

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3

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2

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Solution

The correct option is C $3$
Factors of $1955 = 5 \times 17 \times 23$
Number of factors are $3.$
Therefore, $C$ is the correct answer.

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Similar questions

1955

The number of distinct prime factors in (216) $^{3 / 5}$ (2500) $^{2 / 5}$ (300) $^{1 / 5}$ is

N = 2^{5} \times 3^{7} \times 9^{2} \times 11^{4} \times 13^{3}

(216)^{\frac{3}{5}} \times (2500)^{\frac{2}{5}} \times (300)^{\frac{1}{5}}

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