Question

The number of protons, neutrons and electrons in ${}_{71}^{175}Lu$ respectively, are

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> NEET 2020

• A. $175,104\text{and}71$
• B. $71,71\text{and}104$
• C. $71,104\text{and}71$
• D. $104,71\text{and}71$

Answer 1

The correct option is C $71,104\text{and}71$

${}_{71}^{175}Lu$
Here,
$n_p=n_e=71n_p+n_n=175n_n=175-71=104$
Hence, option (d) is correct.