The number of protons, neutrons and electrons in 14058Ce respectively are
A
140,58 and 58
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B
58,58 and 82
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C
58,82 and 58
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D
82,58 and 58
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Solution
The correct option is C58,82 and 58 Number of protons = atomic number =58
Number of electrons = Number of protons =58
Number of neutron = Mass number – Atomic number =140−58=82