Question

The number of protons, neutrons and electrons in $\underset{71}{175}$ Lu , respectively, are :

• A. 71, 104 and 71
• B. 104, 71 and 71
• C. 175, 104 and 71
• D. 71, 71 and 104

Answer 1

The correct option is A 71, 104 and 71

${}_{\left(p\right)=71}^{n+p=175}Lu$
$\therefore$ no. of protons = 71
no. of neutrons = 175 – 71 = 104
no. of electrons = 71