The correct option is C 3
Let ax2+bx+c=0 ⋯(1) has roots α,β
Equation having roots α2,β2 is f(√x)=0
i.e., ax+b√x+c=0
⇒ax+c=−b√x
⇒a2x2+(2ac−b2)x+c2=0 ⋯(2)
(1) and (2) represent the same equation.
⇒a=a2, b=2ac−b2, c=c2
⇒a=1 as a=0 is not possible
and c=0,1
Case 1: b=2ac−b2 and a=1,c=0
⇒b+b2=0
⇒b=0 or b=−1
Possible quadratic equations are
x2=0
x2−x=0
Case 2: b=2ac−b2 and a=1,c=1
⇒b2+b−2=0
⇒b=−2 or b=1
Possible quadratic equations are
x2−2x+1=0
x2+x+1=0, Not possible as it has non-real roots.