Question

The number of radial nodes and angular nodes for d-orbital can be represented as:

• A. $(n-2)\text{radial nodes}+1\text{angular node}=(n-1)\text{total nodes}$
• B. $(n-1)\text{radial nodes}+1\text{angular node}=(n-1)\text{total nodes}$
• C. $(n-3)\text{radial nodes}+2\text{angular nodes}=(n-l-1)\text{total nodes}$
• D. $(n-3)\text{radial nodes}+2\text{angular nodes}=(n-1)\text{total nodes}$

Answer 1

The correct option is D $(n-3)\text{radial nodes}+2\text{angular nodes}=(n-1)\text{total nodes}$

Number of radial nodes $=n-l-1$
Number of angular nodes $=l$
∴Total number of nodes $=n-l-1+l=n-1$
For d-orbital, $l=2$,
thus number of radial nodes $=n-2-1=n-3$
and number of angular nodes $=l=2$
Total nodes $=n-1$