Question

The number of radial nodes and angular nodes for d-orbital can be represented as:

• A. (n-2) radial nodes + 1 angular node = (n-1) total nodes
• B. (n-1) radial nodes + 1 angular node = (n-1) total nodes
• C. (n-3) radial nodes + 2 angular node = (n-l-1) total nodes
• D. (n-3) radial nodes + 2 angular node = (n-1) total nodes

Answer 1

The correct option is D (n-3) radial nodes + 2 angular node = (n-1) total nodes

Number of radial nodes $=n-l-1$

Number of angular nodes $=l$

$\therefore$Total number of nodes $=n-l-1+l=n-1$

For d-orbital, $l=2$,

thus number of radial nodes $=n-2-1=n-3$

and number of angular nodes $=l=2$

Total nodes$=n-1$