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Question

The number of rational root of (x+1)(x+2)(x+3)(x+4)=24 is:

A
3
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B
2
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C
1
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D
0
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Solution

The correct option is B 2
(x+1)(x+2)(x+3)(x+4)=24
x4+10x3+35x2+50x=x.(x3+10x2+35x+50)
By hit and trail method we have x=5 as root of (x3+10x2+35x+50) dividing it with the equation we get quotient
x.(x+5)(x2+5x+10)
(x2+5x+10) has complex irrational roots
Hence the rational roots are x=5,0

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