The number of rational terms in (1+√2+8√3)6 is
7
(1+√2+8√3)6=6C0+6C1(√2+8√3)+6C2(√2+8√3)3+⋯+6C6(√2+8√3)6
In (√2+8√3)6, Tr+1=6Cr(√2)6−r.(8√3)r
It is rational if r = 0, 6. Similarly in other cases
∴ The number of rational terms = 1 + 0 + 1 + 1 + 1 + 1 + 2 = 7