The correct option is A 6
The general term of the above expression will be
6Cr(√2+313)r
=6CrrCk2r−k23k3
Where
rϵ[0,6] and k≤r.
Hence for rational terms, k has to be a multiple of 3.
Therefore k=0,3,6
For
k=0, r has to be a multiple of 2.
Therefore
k=0;r=0,2,4,6
For k=3;r=5
For k=6;r=6
Hence in total we have 6 rational terms.