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Question

The number of rational terms in the expansion of (1+2+33)6 is

A
6
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B
7
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C
5
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D
8
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Solution

The correct option is A 6
The general term of the above expression will be
6Cr(2+313)r
=6CrrCk2rk23k3
Where
rϵ[0,6] and kr.
Hence for rational terms, k has to be a multiple of 3.
Therefore k=0,3,6
For
k=0, r has to be a multiple of 2.
Therefore
k=0;r=0,2,4,6
For k=3;r=5
For k=6;r=6
Hence in total we have 6 rational terms.

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