Question

The number of real roots in the equation $x^2-3x+5=0$ is:

• A. 0
• B. 1
• C. 2
• D. Infinite

Answer 1

The correct option is A

0

The given equation is $x^2-3x+5=0$
Now, this is a quadratic equation.
If we compare to the standard form $a{x}^2+bx+c=0,a=1,b=-3$ and $c=5.$
The discriminant, $b^2-4ac=(-3{)}^2-4(1\left)\right(5)=9-20=-11$.
Since, $b^2-4ac<0$, the equation will have no real roots.