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Question

The number of real roots of the equation πcosxπ4=0 is

A
0
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B
1
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C
3
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D
None
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Solution

The correct option is A 0
Given πcosxπ4=0
πcosx=π+4
As we know that
cosx[1,1]πcosx[1π,π]LHSπ
RHS=π+4>>π
So there is no solution for which LHS and RHS will be equal
Number of real roots is 0

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