The number of real roots of the equation $| x |^{2} - 3 | x | + 2 = 0$ is

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $4$
${ | x |}^{2} - 3 | x | + 2 = 0 l e t | x | b e t, t \geq 0 t^{2} - 3 t + 2 = 0 (t - 2) (t - 1) = 0 ∴ t = 2 o r 1 w h e r e t = 1 | x | = 1 ∴ x = + 1, - 1 w h e n t = 2 | x | = 2 ∴ x = + 2, - 2 s o 4 r e a l r o o t s$

Suggest Corrections

Similar questions

x^{2} + 3 |x| + 2 = 0

Write the number of real roots of the equation $(x - 1)^{2} + (x - 2)^{2} + (x - 3)^{2} = 0$

(x - 1)^{2} + (x - 2)^{2} + (x - 3)^{2} + (x - 4)^{2} + . . . . . + (x - n)^{2} = 0

(x + 1) (x + 2) (x + 3) (x + 4) = 120

Join BYJU'S Learning Program