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Byju's Answer
Standard XII
Mathematics
Inequalities Involving Modulus Function
The number of...
Question
The number of real solution of the equation
|
a
x
−
2
|
+
|
8
−
a
x
|
<
5
,
a
∈
R
is
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Solution
Given:
|
a
x
−
2
|
+
|
8
−
a
x
|
<
5
Assuming
a
x
=
t
⇒
|
t
−
2
|
+
|
8
−
t
|
<
5
Minimum value of
|
a
|
+
|
b
|
is
|
a
+
b
|
⇒
min
(
|
t
−
2
|
+
|
8
−
t
|
)
=
|
t
−
2
+
8
−
t
|
⇒
min
(
|
t
−
2
|
+
|
8
−
t
|
)
=
|
6
|
>
5
Hence, no solution exists.
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Inequalities Involving Modulus Function
Standard XII Mathematics
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