The number of real solution of the equation $| x^{2} | - 3 | x | + 2 = 0$

4

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Solution

The correct option is D $4$
Now,
$| x^{2} | - 3 | x | + 2 = 0$
or, $| x |^{2} - 3 | x | + 2 = 0$
or, $(| x | - 2) (| x | - 1) = 0$
or, $| x | = 2, | x | = 1$
or, $x = \pm 2, x = \pm 1$ .
So four real solution are there for the given quadratic equation.

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