Question

The number of real solution(s) of the equation $e^x+x=0$ is

• A. $0$
• B. $1$
• C. $2$
• D. $3$

Answer 1

The correct option is B $1$

The number of real solutions of the equation $e^x+x=0$ is equal to the number of point of intersection of the curves $y=e^x$ and $y=-x,$ shown as

It is evident from the graph that these curves intersects at one point only.
$\therefore$ There is only $1$ solution.