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Byju's Answer
Standard XII
Mathematics
Fundamental Laws of Logarithms
The number of...
Question
The number of real solution(s) of the equation
log
4
(
1
+
x
4
)
2
=
2
−
log
2
(
4
+
x
2
)
is
Open in App
Solution
log
4
(
1
+
x
4
)
2
=
2
−
log
2
(
4
+
x
2
)
⇒
log
2
2
(
1
+
x
4
)
2
=
2
−
log
2
(
4
+
x
2
)
⇒
log
2
(
1
+
x
4
)
=
2
−
log
2
(
4
+
x
2
)
⇒
log
2
(
1
+
x
4
)
+
log
2
(
4
+
x
2
)
=
2
⇒
log
2
(
(
1
+
x
4
)
(
4
+
x
2
)
)
=
2
⇒
(
1
+
x
4
)
(
4
+
x
2
)
=
4
We know that,
1
+
x
4
≥
1
4
+
x
2
≥
4
⇒
(
1
+
x
4
)
(
4
+
x
2
)
≥
4
So,
(
1
+
x
4
)
(
4
+
x
2
)
=
4
when
x
=
0
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0
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Fundamental Laws of Logarithms
Standard XII Mathematics
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