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Question

The number of real solution(s) of the equation log4(1+x4)2=2log2(4+x2) is

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Solution

log4(1+x4)2=2log2(4+x2)log22(1+x4)2=2log2(4+x2)
log2(1+x4)=2log2(4+x2)
log2(1+x4)+log2(4+x2)=2
log2((1+x4)(4+x2))=2(1+x4)(4+x2)=4

We know that,
1+x414+x24(1+x4)(4+x2)4
So,
(1+x4)(4+x2)=4 when x=0

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