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Question

The number of real solutions of (x2−7x+11)x2−11x+30=1 is

A
3
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B
4
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C
6
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D
No solution
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Solution

The correct option is A 3
(x27x+11)x211x+30=1
For real solutions,
(x27x+11)=1 or x211x+30=0
=>x27x+10=0 or =>x211x+30=0
=>x25x2x+10=0 or =>x26x5x+30=0
=>x(x5)2(x5)=0 or =>x(x6)5(x6)=0
=>(x5)(x2)=0 or =>(x6)(x5)=0
=>x=5,x=2 or =>x=6,x=5
Thus, number of real solutions are 3
Hence, option 'A' is correct.

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