Question

The number of real solutions of the equation $2|x{|}^2-5|x|+2=0$ is:

• A. 4
• B. 2
• C. none of these

Answer 1

The correct option is A 4

$\begin{array}{cc}& 2|x{|}^2-5|x|+2=0\\ \Rightarrow & (2|x|-1)(|x|-2)=0\\ \therefore & |x|=\frac{1}{2},2\\ \therefore & x=\pm \frac{1}{2},\pm 2\end{array}$