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Question

The number of real solutions of the equation cos7x+sin4x=1 the inerval[π,π]is

A
2
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B
3
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C
5
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D
none of these
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Solution

The correct option is B 3
Given, cos7x+sin4x=1
cos7x=1sin4x=(1sin2x)(1+sin2x)=cos2x(2cos2x)
cos2x(cos5x+cos2x2)=0
cosx=0x=π2,π2
cos5x+cos2x=2 we know 1cosx1
cosx=1 is the only solution x=0
Thus, number of solutions in the given interval is 3.
Hence, option 'B' is correct.

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