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Question

The number of real solutions of the equation (sinx−x)(cosx−x2)=0 is

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is B 3
Given,
(sinxx)(cosxx2)=0
sinx=x or cosx=x2
Now, if sinx=x, then only one solution i.e. x=0 is possible.
Also, if cosx=x2, then two solutions are possible.
Hence, there are total 3 solutions.

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