The number of real solutions of the equation x2+3|x|+2 =0 is:
0
1
2
4
⇒x2+3|x|+2 = 0 ⇒|x|2+3|x|+2 = 0
⇒(|x|+1)(|x|+2) = 0
⇒|x| = -1, |x| = -2
⇒ equation has no real root.