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Question

The number of real solutions of the equation |x|2 – 3|x| + 2 = 0 is:

A
4
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B
1
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C
3
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D
2
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Solution

The correct option is A 4

The expression can be rewritten as

(|x| - 1)(|x| - 2) = 0. x = {-1, +1, -2, +2}

Or, we can say, If x is greater than 0.

x2 – 3x + 2 = 0

(x - 2) (x - 1) = 0

x = {1, 2}

If x is less than 0.

x2 + 3x + 2 = 0

(x + 2) (x + 1) = 0

x = { - 1, - 2}

Option (a)


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