The number of real solutions of the equation |x|2 – 3|x| + 2 = 0 is:
The expression can be rewritten as
(|x| - 1)(|x| - 2) = 0. x = {-1, +1, -2, +2}
Or, we can say, If x is greater than 0.
x2 – 3x + 2 = 0
(x - 2) (x - 1) = 0
x = {1, 2}
If x is less than 0.
x2 + 3x + 2 = 0
(x + 2) (x + 1) = 0
x = { - 1, - 2}
Option (a)