The number of real solutions of the equation $| x |^{2} - 3 | x | + 2 = 0$ is:

4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $4$
Given,
$| x |^{2} - 3 | x | + 2 = 0$
or, $(| x | - 2) (| x | - 1) = 0$
or, $| x | = 2$ and $| x | = 1$
or, $x = \pm 2$ and $x = \pm 1$ .
So we have $4$ real solutions.

Suggest Corrections

Similar questions

| x |^{2} - 3 | x | + 2 = 0

2^{3 x^{2} - 7 x + 4} = 1

The number of real solutions of the equation $x^{2} + 3 | x | + 2$ =0 is:

The number of real solutions of the equation $| x |^{2} - 3 | x | + 2 = 0$ are

Join BYJU'S Learning Program